What is the proper formatting for genus names in scientific writing: should they be italicized or no...
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In scientific writing, the formatting of genus names adheres to specific conventions that are crucial for clarity, precision, and universal understanding across the scientific community. These conventions are part of the broader guidelines provided by the International Code of Nomenclature for algae, fungi, and plants (ICN) and the International Code of Zoological Nomenclature (ICZN). Here, we will explore the proper formatting for genus names and discuss its implications for the classification and identification of species within a genus.
In scientific writing, the formatting of genus names adheres to specific conventions that are crucial for clarity, precision, and universal understanding across the scientific community. These conventions are part of the broader guidelines provided by the International Code of Nomenclature for algae, fungi, and plants (ICN) and the International Code of Zoological Nomenclature (ICZN). Here, we will explore the proper formatting for genus names and discuss its implications for the classification and identification of species within a genus.
Step 1: Understanding the Importance of Genus Names The genus is a rank in the biological classification (taxonomy) that is higher than species and lower than family. Each species is identified by two names (binomial nomenclature): the genus name and the species name (specific epithet). For example, in *Homo sapiens*, *Homo* is the genus, and *sapiens* is the species name.
Step 2: Formatting of Genus Names According to both the ICN and ICZN, the genus name must be: - Italicized: This helps distinguish the genus from other text, clarifying that it is a scientific term. - Capitalized: The first letter of the genus name is always capitalized.
For example, the correct formatting for the genus of the common house cat is *Felis*. This italicization and capitalization apply regardless of the medium of the publication, whether printed or digital.
Step 3: Implications for Classification and Identification The consistent and correct formatting of genus names is not merely a matter of typographic convention but plays a critical role in scientific communication. Here’s how:
- Clarity and Precision: Proper formatting helps prevent confusion between general terms and scientific terms, which is crucial in scientific texts where precision is paramount. - Universal Standardization: It ensures that the same format is used across different countries and languages, facilitating effective global communication in the scientific community. - Aid in Research: Correctly formatted names help researchers quickly identify that the text refers to biological taxa, which is particularly useful in databases and search engines. - Taxonomic Classification: Proper use of genus names aids in the accurate classification of species, as each species must be placed within a genus. This hierarchical placement helps in understanding evolutionary relationships and ecological niches.
Step 4: Application in Species Identification When identifying a species, the genus name serves as the first key identifier, which is then followed by the specific epithet. The correct use of formatting in the genus name ensures that there is no ambiguity in scientific records, research papers, and educational materials. For instance, distinguishing between *Panthera leo* (lion) and *Panthera pardus* (leopard) highlights the importance of both genus and species names in the classification system.
Conclusion In summary, the genus names in scientific writing should always be italicized and capitalized. This standardization is essential for maintaining clarity, ensuring accurate scientific communication, and aiding in the classification and identification of species within a genus. Adhering to these conventions supports the foundational goals of taxonomy and enhances the precision of biological sciences.
Exercise 9-Consider a square ABCD with points M and N on AB such that lines DM and CN intersect outside at E
Structure Classification
Arithmetic-Geometric Mean Inequality
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Exercise 9-Consider a square ABCD with points M and N on AB such that lines DM and CN intersect outside at E
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Here we have another word problem in geometry.
I'll just explain instead of reading it out.
Basically what we have here is a square A, B, C, D,
which means that all 4 sides are equal and all the angles are 90 degrees.
What more is we have a point E outside
the square in such a way that if we connect it to D and to C,
then this is an isosceles triangle.
What that means is that this side,
these are the legs of the isosceles triangle and this are equal in
length and where they cut is M and N. Now,
what we're interested in is what should the length of AM be,
and let's call this one x.
Now, the sum of the areas,
I'll just shade it.
The sum of all these 3 triangles has got to be minimized.
That's an indication this is going to be our y or a function of x.
Now, before we get started,
I just want to say from geometry we can tell.
From geometry, we can conclude that this is also x.
You can see it by symmetry.
But if you really want a more precise reason, well,
these 2 green triangles are congruent because we have 2 angles.
We have 90 degrees and 90 degrees.
We have this side,
and that's what I forgot to say,
that the side is 10 centimeters.
This is 10 and this is 10 and they're all 10.
The reason that this angle is also equal to this angle is
because these angles are equal because they're the base angles of an isosceles triangle.
Let's say this is alpha,
and this is alpha, this alternate with this,
this alternates with this,
2 angles in the side, the congruent.
This is also x.
Enough with the geometry.
Now, we want to get an expression for the sum of the 3 triangles,
which I'll call f of x,
where x is our independent variable.
Let's see. Let's do this triangle first.
It's 90 degrees, so it's just base times height.
It's x times 10 over 2. x times 10 over 2.
Likewise, this one is congruent,
so this is also x times 10 over 2.
Now, the hard part,
what about this triangle, the one at the top?
How do I find the area of this?
Well, I need half base times height.
The base is not so bad because this whole thing is 10,
and here I subtract x and x.
This bit is 10 minus 2x.
I've got the base. The question is,
what about the height?
Let me draw that in a different color.
What I need to know is the height of this triangle,
and we'll call that h. The way I'm going to find h is using similar triangles.
Now, this bit here after the h is 10.
What I claim is that this big isosceles triangle
is similar to this small isosceles triangle.
Well, I need for similarity of 2 triangles.
I've got alpha and alpha,
and here I've got alpha and alpha, so they're similar.
If there are similar,
then I can compare corresponding sides.
I can compare the heights and the bases to be in the same ratio.
What I'm saying is that in this triangle,
the ratio of h,
the height of the small triangle to the height of the big triangle,
which is h plus 10,
is going to be in the same ratio as the base of this to the base of this.
It's the ratio of 10 minus 2x to 10.
What this means is that this over this equals this over this.
What you do is you just multiply the outsides and the inside.
h times 10 or 10 times h is equal to h plus 10
times 10 minus 2x.10h is equal.
Now, to multiply out h times both of these,
I've got 10h minus 2hx,
and then 10 times both of these,
so plus 100 minus 20x.
I see that 10h and 10h cancel.
Well, let's bring this to the other side.
I've got 2xh equals 100 minus 20x.
I'm trying to isolate h. Finally,
h equals 100 minus 20x over 2x.
If I divide it out,100 over 2x is 50 over x,
and 20x over 2x is just 10.
Now, I have a formula for h in terms of x.
Now, I'm going to add the missing piece.
The missing piece here is this triangle,
and I need half the base times the height, so it's half.
The base is 10 minus 2x times
the height h. But I don't want the height h. I don't want to copy this line.
Again, I'm just going to put h for what it is equal to here.
Let's erase that h. Instead,
I'm going to put 50 over x minus 10.
This is our f of x.
This is the function that's equal to the area of the green shaded bits.
I'm going to simplify this before we go any further because this looks a mess.
Let's see what we can get here.
Well, this plus this is just going to be 10x.
It's over 2 and over 2,
so it's just 10x for this bit.
This half can go.
Let's see, if I get rid of this half,
I can make this 5 and this just x,
so it's 5 minus x.
Let's multiply out what's here.
5 minus x times this.
The 5 with these 2 goes as 250 over x minus 50,
and then the minus x gives me minus 50.
Then minus with minus is plus,
so it's plus 10x.
Let's see what we can collect here.
10x and 10x is 20x.
Minus 50 and minus 50 is minus 100.
Plus 250 over x,
so this is what f of x equals.
I'll just highlight that.
That gives the sum of the 3 areas in terms of x.
Okay. This is what we want to minimize.
This is what we're going to differentiate and then set to 0. f prime of x is equal to 20.
This gives nothing, and the derivative of 1 over x is minus 1 over x squared,
so we get minus 250 over x squared.
That's the derivative.
Now, we want to look for suspects for extra mass.
We set f prime of x equals to 0.
That gives us that this minus this equals 0,
20 minus 250 over x squared equals 0.
250 over x squared is equal to 20.
Then we can switch between these 2 and say that x squared is 250 over 20.
This comes out to be 12-and-a-half I guess, 12.5.
X has to be positive,
so x is the plus square root of 12.5,
and that's approximately equal to 3.5.
But we still haven't shown that is truly a minimum.
What we need to do is,
well the several possibilities not going to use the table method.
The table means that I make a table as follows.
I have 3 rows in it.
I have x, I have f prime of x,
and I have f of x. I put in all the suspicious or candidates for extra math.
I only have 1, and that's the square root of 12.5.
That's, as I said, is roughly 3.5.
At this point is where the f prime is 0.
That's how we got to it.
What I need to know is if it's increasing or decreasing before or after.
Let's take 0.3 and 0.4,
which are around it.
That's why I need to know approximately.
I need to know something smaller, something bigger.
If I put in x equals 3 in f prime,
so I get 20 minus 250 over 9.
Well, it's more than 250 over 10.
It's more than 25. This comes out negative.
Basically, what I'm saying is this comes out negative.
If I put in x equals 4, then x squared is 16.
250 over 16, well it's less than 16 because 16 squared is 256,
and that means that this is positive or you can do it with the calculator also.
Anyway, it's negative here,
so the function is decreasing,
positive here the function is increasing.
Here at the point itself,
between decreasing and increasing,
it must be a minimum.
What we have shown is that indeed x,
which is what we had to find,
is square root of 12.5,
and we are done.
This video explains how to solve a geometry word problem involving a square and an isosceles triangle. The goal is to find the length of AM, which is denoted as x, in order to minimize the sum of the areas of the three triangles. Through the use of congruent angles, similar triangles, and the formula for the area of a triangle, the speaker is able to determine that x is equal to the square root of 12.5. This is done by setting the derivative of the function equal to 0 and then using the table method to prove that x is a minimum.
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